What is the weight of 2 square feet of 22-gauge stainless steel?

Master the Florida Roofing Trade Exam with flashcards and multiple choice questions. Analyze hints and explanations for confident preparation and success.

Multiple Choice

What is the weight of 2 square feet of 22-gauge stainless steel?

Explanation:
Weight is found from density times volume. For a sheet, volume equals thickness times area. Convert the area to square inches: 2 ft^2 is 288 in^2. Use the thickness for 22-gauge stainless, which is about 0.032 inches. The volume is 288 × 0.032 = 9.216 cubic inches. Stainless steel density is about 0.284 lb per cubic inch, so the weight is 9.216 × 0.284 ≈ 2.62 pounds. Therefore, 2 square feet of 22‑gauge stainless steel weighs about 2.62 pounds.

Weight is found from density times volume. For a sheet, volume equals thickness times area. Convert the area to square inches: 2 ft^2 is 288 in^2. Use the thickness for 22-gauge stainless, which is about 0.032 inches. The volume is 288 × 0.032 = 9.216 cubic inches. Stainless steel density is about 0.284 lb per cubic inch, so the weight is 9.216 × 0.284 ≈ 2.62 pounds. Therefore, 2 square feet of 22‑gauge stainless steel weighs about 2.62 pounds.

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